문제
Given an array of integers nums
and an integer target
, return indices of the two numbers such that they add up to target
.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
You can return the answer in any order.
Example 1:
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Input: nums = [2,7,11,15], target = 9
Output: [0,1]
Explanation: Because nums[0] + nums[1] == 9, we return [0, 1].
Example 2:
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Input: nums = [3,2,4], target = 6
Output: [1,2]
Example 3:
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Input: nums = [3,3], target = 6
Output: [0,1]
Constraints:
2 <= nums.length <= 104
109 <= nums[i] <= 109
109 <= target <= 109
- Only one valid answer exists.
[풀이]
1. 2중 for문 사용
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class Solution:
def twoSum(self, nums: List[int], target: int) -> List[int]:
for i in range(len(nums)):
for j in range(i+1, len(nums)):
if nums[i]+nums[j] == target:
return [i, j]
else:
continue
📌주목
- Two Sum 2 문제와의 차이점: sorting이 되어있는 문자열인지 아닌지